allocate an array

[Simon]

Hello everybody,

I've got a problem. I'm trying to allocate an array inside a function with
Parameter int n:
main(){
int i;
....
i = strlen(ch);
array(i);
....
}


int array ( int n ){
int a[n];
....
}
but when i compile:

error C2057: expected constant expression
error C2466: cannot allocate an array of constant size 0
error C2133: 'a' : unknown size
error C2057: expected constant expression
error C2466: cannot allocate an array of constant size 0


how can i do now?
Thank u in advance for your afforts.

 

[Marc Boyer]

Hello everybody,
int array ( int n ){
int a[n];
...
}
but when i compile:

error C2057: expected constant expression
error C2466: cannot allocate an array of constant size 0
error C2133: 'a' : unknown size
error C2057: expected constant expression
error C2466: cannot allocate an array of constant size 0

Perhaps because your compiler does not accept C99 ?
To my knowledge, this construction is in C99, but not
in C89.
Change your compiler, or use "malloc".

Marc Boyer

 

[Chris Dollin]

I've got a problem. I'm trying to allocate an array inside a function with
Parameter int n:
main(){
int i;
...
i = strlen(ch);
array(i);
...
}


int array ( int n ){
int a[n];
...
}

You can't do that in (pre-99) C. Instead of allocating an array,
allocate some heap space (and remember to free it), eg:

int *a = malloc( n * sizeof (*a) );

Remember to #include <stdlib.h>.

 

[Simon]

thanks a lot.

i got it

I've got a problem. I'm trying to allocate an array inside a function with
Parameter int n:
main(){
int i;
...
i = strlen(ch);
array(i);
...
}


int array ( int n ){
int a[n];
...
}

You can't do that in (pre-99) C. Instead of allocating an array,
allocate some heap space (and remember to free it), eg:

int *a = malloc( n * sizeof (*a) );

Remember to #include <stdlib.h>.