array to string conversion

[Clement Ow]

Hi, I have 2 arrays(which is part of the hash):

ex = {}
ex[0] = ["xls", "ini", "20080326"]
ex[1] = ["gif", "xls", "rb"]

All i managed to convert is(using .to_s):
str[0] = "xlsini20080326"
str[1] = "gifxlsrb"

but i want to convert each array into a string, something like
str[0] = "xls,ini,20080326"
str[1] = "gif,xls,rb"

where they are seperated by a comma.. Any clean way of doin this?

 

[Stefano Crocco]

Hi, I have 2 arrays(which is part of the hash):

ex = {}
ex[0] = ["xls", "ini", "20080326"]
ex[1] = ["gif", "xls", "rb"]

All i managed to convert is(using .to_s):
str[0] = "xlsini20080326"
str[1] = "gifxlsrb"

but i want to convert each array into a string, something like
str[0] = "xls,ini,20080326"
str[1] = "gif,xls,rb"

where they are seperated by a comma.. Any clean way of doin this?

ex[0].join ','

Stefano

 

[Sandro Paganotti]

[Note: parts of this message were removed to make it a legal post.]

Try this:
irb(main):004:0> ex
=> {0=>["xls", "ini", "20080326"], 1=>["gif", "xls", "rb"]}
irb(main):005:0> ex = Hash[*ex.collect{|a,b| [a,b.join(",")]}.flatten]
=> {0=>"xls,ini,20080326", 1=>"gif,xls,rb"}


Sandro

Hi, I have 2 arrays(which is part of the hash):

ex = {}
ex[0] = ["xls", "ini", "20080326"]
ex[1] = ["gif", "xls", "rb"]

All i managed to convert is(using .to_s):
str[0] = "xlsini20080326"
str[1] = "gifxlsrb"

but i want to convert each array into a string, something like
str[0] = "xls,ini,20080326"
str[1] = "gif,xls,rb"

where they are seperated by a comma.. Any clean way of doin this?

ex[0].join ','

Stefano

 

[Clement Ow]

Try this:
irb(main):004:0> ex
=> {0=>["xls", "ini", "20080326"], 1=>["gif", "xls", "rb"]}
irb(main):005:0> ex = Hash[*ex.collect{|a,b| [a,b.join(",")]}.flatten]
=> {0=>"xls,ini,20080326", 1=>"gif,xls,rb"}


Sandro

On Fri, Jun 13, 2008 at 5:53 AM, Stefano Crocco
<[email protected]>

It works! Thanks guys for the input!

 

[Peña, Botp]

From: Sandro Paganotti [mailto:[email protected]]=20
# irb(main):004:0> ex
# =3D> {0=3D>["xls", "ini", "20080326"], 1=3D>["gif", "xls", "rb"]}
# irb(main):005:0> ex =3D Hash[*ex.collect{|a,b| =
[a,b.join(",")]}.flatten]
# =3D> {0=3D>"xls,ini,20080326", 1=3D>"gif,xls,rb"}



irb(main):018:0> ex.inject({}){|h,(v,k)| h[v]=3Dk.join(",");h}
=3D> {0=3D>"xls,ini,20080326", 1=3D>"gif,xls,rb"}


kind regards -botp

 

[alandacosta]

I'm not exactly sure what's up with your hash wrapper. I think it
would be easier as an array wrapper, because indexes would be implicit
to the object, but hopefully this will do the trick; it might be the
easiest way:

ex.map {|i,v| v * "," }
=> ["xls,ini,20080326", "gif,xls,rb"]

 

[Peña, Botp]

From: (e-mail address removed) [mailto:[email protected]]=20
# ex.map {|i,v| v * "," }

i always forget that "*" op on arrays=20
thanks for the reminder

kind regards -botp

 

[Clement Ow]

From: (e-mail address removed) [mailto:[email protected]]
# ex.map {|i,v| v * "," }

i always forget that "*" op on arrays
thanks for the reminder

kind regards -botp

Thank you guys, for your kind inputs! =) it really helped me alot!

However, I now encounter another problem..
Assuming my hash:
ex = {}
ex[0] = [".xls", ".ini", "20080326"]
ex[1] = ["RVG", ".xls", ".rb"]

I need to extract the values in each array with the extentions(values
with periods) into one string and the dir names(values without the
periods) into another string. I've been tryin to figure out but to no
avail, is there a clean way to do that?

 

[Peña, Botp]

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[Clement Ow]

From: (e-mail address removed)
# However, I now encounter another problem..
# Assuming my hash:
# ex = {}
# ex[0] = [".xls", ".ini", "20080326"]
# ex[1] = ["RVG", ".xls", ".rb"]
# I need to extract the values in each array with the extentions(values
# with periods) into one string and the dir names(values without the
# periods) into another string. I've been tryin to figure out but to no
# avail, is there a clean way to do that?

Hi Clement, pardon me because i cannot picture the problem.
can you give an example?

Hi botp,

Assuming I have my hash:

ex = {}
ex[0] = [".xls", ".ini", "20080326"]
ex[1] = ["RVG", ".xls", ".rb"]

The result i would want:
str1 = [".xls", ".ini", ".xls", ".rb"]
str2 = ["20080326", "RVG"]

Is there any way i can do this?
Thanks.

Regards,
Clement

 

[Stefano Crocco]

Hi botp,

Assuming I have my hash:

ex = {}
ex[0] = [".xls", ".ini", "20080326"]
ex[1] = ["RVG", ".xls", ".rb"]

The result i would want:
str1 = [".xls", ".ini", ".xls", ".rb"]
str2 = ["20080326", "RVG"]

Is there any way i can do this?
Thanks.

Regards,
Clement

Try looking at Enumerable#partition. A possible way to do this is:

res = ex.values.flatten.partition{|v| v[0..0] == '.'}
p res
=> [[".xls", ".ini", ".xls", ".rb"], ["20080326", "RVG"]]

Stefano

 

[Peña, Botp]

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