assign the array returned by String.split to a variable

C

Catsquotl

Hi

i have the following method
-----
def create
length = @txt.length
i = 0
while i < (length + 1)
line = @TxT
line.split(',')
#@arr.push(a)
i += 1
end
end
-------
this works but as soon as i take out the comment.
i get an error something about private method split beeing called on a
nil object.
I found out that this has to do with split that has to be called by self
or something.

what i like to do is have an array of the split arrays.
any ideas?

greet Eelco
 
7

7stud --

assign the array returned by String.split to a variable

str = "hello,world"
arr = str.split(",")
p arr

--output:--
["hello", "world"]
 
J

John W Higgins

[Note: parts of this message were removed to make it a legal post.]

Hi



what i like to do is have an array of the split arrays.
any ideas?


You would want something like this

def create
ary = @txt.collect{ |t| t.split(',') }
end

Basically collect takes your initial array and runs through each element and
creates a new array based on the results of the block.

John
 
B

Brian Candler

Catsquotl said:
Hi

i have the following method
-----
def create
length = @txt.length
i = 0
while i < (length + 1)
line = @txt
line.split(',')
#@arr.push(a)
i += 1
end
end


This means that @arr is nil, that is, you are doing

nil.push(a)

So you need to initialize it first:

@arr = []

There are a few other errors in your code, for example you didn't assign
to a:

a = line.split(',')
@arr.push(a)

and your loop should be while i < length, not while i < length+1. As has
been pointed out, there are more ruby-like ways to do this loop.
 

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