assigning array to a scalar variable

[venkatesh.naughty]

Hi all,
How to assign array variable to a scalar retaining the content of the
array in the scalar variable not number of elements ;
eg:
@array={"hi","venkatesh"};
$x=@array;
I dont want $x to store 2
instead to store hi venkatesh

 

[Peter Makholm]

@array={"hi","venkatesh"};
$x=@array;

I'm not sure this does what you believe it does. In any case you want
to read the perlreftut document:

http://search.cpan.org/~rgarcia/perl-5.10.0/pod/perlreftut.pod

//Makholm

 

[John W. Krahn]

Hi all,
How to assign array variable to a scalar retaining the content of the
array in the scalar variable not number of elements ;
eg:
@array={"hi","venkatesh"};
$x=@array;
I dont want $x to store 2
instead to store hi venkatesh

Use the reference operator \.

my $x = \@array;

This will give $x a reference to the array @array so if you modify an
element of the array from $x it will also modify the original array's data.



John

 

[Oliver Abram]

Hi all,
How to assign array variable to a scalar retaining the content of the
array in the scalar variable not number of elements ;
eg:
@array={"hi","venkatesh"};
$x=@array;
I dont want $x to store 2
instead to store hi venkatesh

Or maybe this one:


@array = qw (hi venkatesh whats up);

foreach (@array)
{
$x .= "$_ ";
}
print $x;
#now $x contains hi venkatesh whats up

 

[Gunnar Hjalmarsson]

How to assign array variable to a scalar retaining the content of the
array in the scalar variable not number of elements ;
eg:
@array={"hi","venkatesh"};
$x=@array;
I dont want $x to store 2
instead to store hi venkatesh

$x = join ' ', %{ $array[0] };

If you rather mean that you have the array

@array = ("hi","venkatesh");

you can simply do

$x = "@array";

HTH

 

[Ben Morrow]

How to assign array variable to a scalar retaining the content of the
array in the scalar variable not number of elements ;
eg:
@array={"hi","venkatesh"};
$x=@array;
I dont want $x to store 2
instead to store hi venkatesh

$x = join ' ', %{ $array[0] };

If you rather mean that you have the array

@array = ("hi","venkatesh");

you can simply do

$x = "@array";

....but be careful about $". Either of

{
local $" = ' ';
$x = "@array";
}

or

$x = join ' ', @array;

would be safer.

Ben

 

[Tad J McClellan]

Or maybe this one:


@array = qw (hi venkatesh whats up);

foreach (@array)
{
$x .= "$_ ";
}

That leaves an extra space character at the end of $x.

$x = join ' ', @array; # no trailing space

 

[Jürgen Exner]

Hi all,
How to assign array variable to a scalar retaining the content of the
array in the scalar variable not number of elements ;
eg:
@array={"hi","venkatesh"};
$x=@array;
I dont want $x to store 2

Well, it doesn't. $x contains 1 because the only element in @array is the
reference to the anonymous hash {'hi' => 'venkatesh'}

instead to store hi venkatesh

Do you mean the text 'hi venkatesh'?
Luckily Perl is smart enough to allow using join() on hashes, too. So you
can just join the key and value of the anonymous hash:

print join (' ', %{$array[0]});

Jue