Beginner's question

[Wong]

Hi gurus,

This macro does not look like a common one. Is this a function ?

#define Uint16(value) Uint8(value) , Uint8(value << 1)

Thanks in advance.

 

[dandelion]

Hi gurus,

This macro does not look like a common one. Is this a function ?

#define Uint16(value) Uint8(value) , Uint8(value << 1)

Nope. It's a macro. Anything which is '#defined' is.

 

[Richard Bos]

This macro does not look like a common one. Is this a function ?

#define Uint16(value) Uint8(value) , Uint8(value << 1)

No, it's a function-like macro. It takes one parameter, and expands to
the text behind it with "value" replaced by that parameter. For example:

a=Uint16(24);

is expanded to

a=Uint8(24) , Uint8(24 << 1);

in which both Uint8's are probably macros as well, so they would now be
expanded, too.

This does not look like a very useful macro to me, but it is a macro all
the same.

Richard

 

[Flash Gordon]

Nope. It's a macro. Anything which is '#defined' is.

It looks to me like it is also probably wrong, as well as being bad
style for not being spelled in upper case.