Better one liner to sum a column?

[Sammyo]

Is there a cleaner way to do this?

$ cat example_data
1 foo 3943
2 bar 8989
3 baz 9088

$ ruby -e 'i=0;ARGF.each{|l| i += l.split[2].to_i};p i' example_data
22020

As a relative newby I tried inject which seemed cool but
converting from string to int seem defeated that approach.

-sam

 

[Ross Bamford]

Is there a cleaner way to do this?

$ cat example_data
1 foo 3943
2 bar 8989
3 baz 9088

$ ruby -e 'i=0;ARGF.each{|l| i += l.split[2].to_i};p i' example_data
22020

As a relative newby I tried inject which seemed cool but
converting from string to int seem defeated that approach.

How about:

$ ruby -e 'p ARGF.inject(0){|a,b|a+b.split[2].to_i}' example_data
22020

 

[Robert Klemme]

Is there a cleaner way to do this?

$ cat example_data
1 foo 3943
2 bar 8989
3 baz 9088

$ ruby -e 'i=0;ARGF.each{|l| i += l.split[2].to_i};p i' example_data
22020

As a relative newby I tried inject which seemed cool but
converting from string to int seem defeated that approach.

How about:

$ ruby -e 'p ARGF.inject(0){|a,b|a+b.split[2].to_i}' example_data
22020

You can also do it awk style:

robert@fussel /cygdrive/c/Temp
$ cat dat
1 foo 100
2 bar 32
3 xxx 982

robert@fussel /cygdrive/c/Temp
$ ruby -nae 'BEGIN {$s=0}; $s+=$F[2].to_i; END {puts $s}' dat
1114

Kind regards

robert

 

[William James]

Is there a cleaner way to do this?

$ cat example_data
1 foo 3943
2 bar 8989
3 baz 9088

$ ruby -e 'i=0;ARGF.each{|l| i += l.split[2].to_i};p i' example_data
22020

As a relative newby I tried inject which seemed cool but
converting from string to int seem defeated that approach.

-sam

ruby -e 'puts $<.inject(0){|n,s| n + s[/\d+$/].to_i }'