Binary Functor Predicate w/ different parameters

[Shawn McGrath]

Can you use the standard binders (std::bind2nd) on a functor taking two
different parameter types?

Here's my code now:

template <typename T>
struct compareValString : public std::binary_function
<resources::ScopedType<T>, std::string, bool >
{
typedef typename resources::ScopedType<T> ST;
inline bool operator()(const ST &v, const std::string &n)
{
return false;
}
};

....

values.erase(std::remove_if(values.begin(), values.end(),
std::bind2nd(compareValString<ResourceType>(), *it)), values.end());

//it is an iterator for a vector of strings.

 

[Daniel T.]

Can you use the standard binders (std::bind2nd) on a functor taking two
different parameter types?
Yes.

Here's my code now:

template <typename T>
struct compareValString : public std::binary_function
<resources::ScopedType<T>, std::string, bool >
{
typedef typename resources::ScopedType<T> ST;
inline bool operator()(const ST &v, const std::string &n)
{
return false;
}
};

The function should be const. As in:

bool operator()( const ST& v, const std::string& n ) const

 

[Daniel T.]

Can you use the standard binders (std::bind2nd) on a functor taking two
different parameter types?
Yes.

Here's my code now:

template <typename T>
struct compareValString : public std::binary_function
<resources::ScopedType<T>, std::string, bool >
{
typedef typename resources::ScopedType<T> ST;
inline bool operator()(const ST &v, const std::string &n)

Should be:
inline bool operator()(const ST &v, const std::string &n) const