bit manuplation

[ali4ever4]

well hi ther i have alittle advanced question about bitmanuplation

if i have a set of bits such as 10110011

which can be any thing arrays of 1 and 0 or may be string or mostly
BitSet

is there is away to convert it to byte or may be to any other premitive
type such as int or char with the rest of the bits be zeros ??!!
hope i will find an answer to my question

 

[klynn47]

Try the wrapper class Integer

 

[Ryan Stewart]

Try the wrapper class Integer

Or Byte or Short or Long. Specifically, the T.parseT() methods, where T is
one of the aforementioned types.

 

[Chris Smith]

well hi ther i have alittle advanced question about bitmanuplation

if i have a set of bits such as 10110011

which can be any thing arrays of 1 and 0 or may be string or mostly
BitSet

You've got answers for String. As for BitSet, the following should
work:

public int bitsetToInt(BitSet bitset)
{
if (bitset.length() > 32) throw new IllegalArgumentException();

int result = 0;
for (int i = 0; i < 32; i++)
{
if (bitset.get(i)) result |= (1 << i);
}

return result;
}

Of course, this code will fail if there are more than 32 bits in the
BitSet. You can modify the above as appropriate for byte, short, or
long if you prefer. It makes no sense to put a bit mask in char, but if
you really wish to do so, then the same code will work.

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