Calling through pointers to member functions

Discussion in 'C++' started by Timothy Madden, Dec 28, 2004.

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    Timothy Madden, Dec 28, 2004
    #1
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  2. [cross-posted]

    Hi

    If I have a pointer to one of my member functions, and the pointer is also a
    member, in the same class, should 'this->' not be used implicitly in the
    class scope to call the pointed function ?

    Something like this:

    class MbxAddress
    {
    protected:
    void LocateAnyMbx()
    {
    }

    void LocateUserMbx()
    {
    }

    public:
    void (MbxAddress::*LocateMbx)();
    MbxAddress(bool fManagers = true)
    {
    if (fManagers)
    LocateMbx = &MbxAddress::LocateAnyMbx;
    else
    LocateMbx = &MbxAddress::LocateUserMbx;
    LocateMbx();
    }
    };

    Here the last call 'LocateMbx()' should work without explicitly writing
    (this->*LocateMbx)();
    because 'this->' is implicit in class scope and
    dereferencing the function pointer to call the referred function is also
    implicit
    anyway.

    Of course in total there should be two uses of 'this->' here:
    - one for the pointer itself since it is a member
    - one for the refered function since it must be applied on an object to be
    called

    I think it would be natural for both uses to be implicit here.
    Please, anyone wants to comment on this ?

    Timothy Madden
    Romania



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    Timothy Madden, Dec 29, 2004
    #2
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  3. "Timothy Madden" <> wrote...
    > If I have a pointer to one of my member functions, and the pointer is also
    > a
    > member, in the same class, should 'this->' not be used implicitly in the
    > class scope to call the pointed function ?


    You shouldn't confuse two syntaxes: this-> and this->*. They are different,
    they have different purpose, and while the former is not always required,
    the latter is required _always_ to call a function through a pointer to
    a member.

    >
    > Something like this:
    >
    > class MbxAddress
    > {
    > protected:
    > void LocateAnyMbx()
    > {
    > }
    >
    > void LocateUserMbx()
    > {
    > }
    >
    > public:
    > void (MbxAddress::*LocateMbx)();
    > MbxAddress(bool fManagers = true)
    > {
    > if (fManagers)
    > LocateMbx = &MbxAddress::LocateAnyMbx;
    > else
    > LocateMbx = &MbxAddress::LocateUserMbx;
    > LocateMbx();
    > }
    > };
    >
    > Here the last call 'LocateMbx()' should work without explicitly writing
    > (this->*LocateMbx)();
    > because 'this->' is implicit in class scope and
    > dereferencing the function pointer to call the referred function is also
    > implicit
    > anyway.
    >
    > Of course in total there should be two uses of 'this->' here:
    > - one for the pointer itself since it is a member
    > - one for the refered function since it must be applied on an object to
    > be
    > called
    >
    > I think it would be natural for both uses to be implicit here.
    > Please, anyone wants to comment on this ?


    What to comment? The ->* is required.

    V
     
    Victor Bazarov, Dec 29, 2004
    #3
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    Timothy Madden, Dec 29, 2004
    #4
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