chr / ord

[Sean McIlroy]

hello

how do i say "chr" and "ord" in the new python? the functions below
(which work in 2.6.6) show what i'm trying to do. thanks if you can
help.

def readbytes(filepath):
return [ord(x) for x in open(filepath,'rb').read()]

def writebytes(numbers,filepath):
open(filepath,'wb').write(''.join([chr(x) for x in numbers]))

 

[Benjamin Kaplan]

hello

how do i say "chr" and "ord" in the new python? the functions below
(which work in 2.6.6) show what i'm trying to do. thanks if you can
help.

def readbytes(filepath):
   return [ord(x) for x in open(filepath,'rb').read()]

Ord should still work the way you expect.

def writebytes(numbers,filepath):
   open(filepath,'wb').write(''.join([chr(x) for x in numbers]))

I haven't played around with python 3 that much, but I believe that
the bytes constructor can take an iterable of ints. So you should be
able to do
open(filepath,'wb').write(bytes(numbers))

 

[Steven D'Aprano]

hello

how do i say "chr" and "ord" in the new python?

"chr" and "ord".

the functions below (which work in 2.6.6)

Can I borrow your time machine, there's some lottery numbers I want to
get.

There is no Python 2.6.6. The latest version of 2.6 is 2.6.4.

show what i'm trying to do. thanks if you can help.

def readbytes(filepath):
return [ord(x) for x in open(filepath,'rb').read()]

def writebytes(numbers,filepath):
open(filepath,'wb').write(''.join([chr(x) for x in numbers]))

Have you tried them in "the new Python" (whatever that is...)? What do
they do that isn't what you expect?

 

[Sean McIlroy]

thanks. that did the trick. in case anyone else is in the same boat as
myself, here are the relevant correspondences:

string <-> [int] bytes <-> [int]