concatenate the elements in each list of a list of lists

[antar2]

I already asked a similar question, but encounter problems with
python...
How can I concatenate the elements in each list of a list of lists

list_of_listsA =

[['klas*', '*', '*'],
['mooi*', '*', '*', '*'],
['arm*', '*', '*(haar)']]

wanted result:

list_of_listsA =

[['klas* * *']
['mooi* * * *']
['arm* * *(haar)']]

Thanks a lot !

 

[Chris]

I already asked a similar question, but encounter problems with
python...
How can I concatenate the elements in each list of a list of lists

list_of_listsA =

[['klas*', '*', '*'],
['mooi*', '*', '*', '*'],
['arm*', '*', '*(haar)']]

wanted result:

list_of_listsA =

[['klas* * *']
['mooi* * * *']
['arm* * *(haar)']]

Thanks a lot !

Nice and easy.

list_of_listsA = [['klas*', '*', '*'],

['mooi*', '*', '*', '*'],
['arm*', '*', '*(haar)']]

[' '.join(l) for l in list_of_listsA]

['klas* * *', 'mooi* * * *', 'arm* * *(haar)']

 

[Michael Schneider]

Am Wed, 23 Jul 2008 08:33:57 -0700 wrote antar2:

I already asked a similar question, but encounter problems with
python...
How can I concatenate the elements in each list of a list of lists

list_of_listsA =

[['klas*', '*', '*'],
['mooi*', '*', '*', '*'],
['arm*', '*', '*(haar)']]

wanted result:

list_of_listsA =

[['klas* * *']
['mooi* * * *']
['arm* * *(haar)']]

Thanks a lot !

Hello,

maybe this will help:

In [5]: list_of_listsA = [['klas*', '*', '*'], ['mooi*', '*', '*', '*'],
['arm*', '* ', '*(haar)']]
In [6]: s = ""
In [7]: print [[s.join(item)] for item in list_of_listsA]
[['klas***'], ['mooi****'], ['arm** *(haar)']]

regards
Michael

 

[Niklas Norrthon]

I already asked a similar question, but encounter problems with
python...
How can I concatenate the elements in each list of a list of lists

list_of_listsA =

[['klas*', '*', '*'],
['mooi*', '*', '*', '*'],
['arm*', '*', '*(haar)']]

wanted result:

list_of_listsA =

[['klas* * *']
['mooi* * * *']
['arm* * *(haar)']]

Thanks a lot !

wanted_result = [[item] for item in map(' '.join, list_of_listsA)]