Convert XML file into InputStream

[Ale]

Hi all,

I need to convert an XML file into an InputStream in order to have an
object and do other work.

This is the fragment, but XML file can't be found (it's of course in
the classpath, I've also tried using an absolute path name):

//START
InputStream stream;
stream = ClassLoader.getSystemResourceAsStream("/com/home/resources");

JAXBContext context = JAXBContext.newInstance(GetChartRequest1.class);
Unmarshaller unmarsh = context.createUnmarshaller();
GetChartRequest1 req = (GetChartRequest1)unmarsh.unmarshal(stream);
//END

Any suggestion ?

Thanks and best regards,
Alex

 

[Lew]

Hi all,

I need to convert an XML file into an InputStream in order to have an
object and do other work.

This is the fragment, but XML file can't be found (it's of course in
the classpath, I've also tried using an absolute path name):

//START
InputStream stream;
stream = ClassLoader.getSystemResourceAsStream("/com/home/resources");

JAXBContext context = JAXBContext.newInstance(GetChartRequest1.class);
Unmarshaller unmarsh = context.createUnmarshaller();
GetChartRequest1 req = (GetChartRequest1)unmarsh.unmarshal(stream);
//END

Don't use 'ClassLoader.getSystemResourceAsStream()', use
'ClassLoader.getResourceAsStream()' or 'Class.getResourceAsStream()'.

 

[markspace]

Hi all,

I need to convert an XML file into an InputStream in order to have an
object and do other work.

This is the fragment, but XML file can't be found (it's of course in
the classpath, I've also tried using an absolute path name):

File not found == it ain't there.

Can you show us the "absolute path" you used? Can you show us a
directory listing from the command prompt to prove that the file really
is where you say it is?

Otherwise, the system is correct, it ain't there.


Other ideas:

Is this a Jar file? Jar files ignore the class path variable.

Is the "resource" inside the Jar file? Or loose on disc? If it's
inside the Jar file, don't use ClassLoader or Class. use getClass().

getClass().getResourceAsStream( "..." );

I just noticed your are calling "getSystemResourceAsStream". That's
almost certainly wrong. System resources live inside the Java JRE, in
rt.jar or some such. If your resource is anywhere else on disc, you
can't get it with getSystemResourceAsStream().


More info please... show us the command line you use to execute the app,
the location of the resource, the class path, etc. Cut and paste
everything directly from your computer screen to your email, so there's
no typos. We have to know exactly what's going on to fix this for you.

 

[Lew]

markspace <wrote:

I just noticed your are calling "getSystemResourceAsStream".  That's
almost certainly wrong.  System resources live inside the Java JRE, in
rt.jar or some such.  If your resource is anywhere else on disc, you
can't get it with getSystemResourceAsStream().

In other words:
Don't use 'ClassLoader.getSystemResourceAsStream()', use
'ClassLoader.getResourceAsStream()' or 'Class.getResourceAsStream()'.