cout2,

[vsgdp]

Why does the first statement output nonsense, but not the second. That
is, why aren't the statements equivelement?

#include<iostream>
#include <cmath>
using namespace std;

int main()
{
cout.operator <<("sin(2)=").operator <<(sin(2)).operator <<(endl);
cout << "sin(2)=" << sin(2) << endl;
}

 

[Stuart Redmann]

Why does the first statement output nonsense, but not the second. That
is, why aren't the statements equivelement?

#include<iostream>
#include <cmath>
using namespace std;

int main()
{
cout.operator <<("sin(2)=").operator <<(sin(2)).operator <<(endl);

cout.operator << "sin(2)="; invokes the member function
ostream:perator<< (const void* param)
and not what you expected:
inline ostream operator<< (ostream& _O, const char *param)
The reason for this is that you explicitely ask for the member function
operator<<, but operator<< for char* is defined as static function (as
most other custom defined stream operators are). What you are seeing is
the address of the string.

cout << "sin(2)=" << sin(2) << endl;
}

You should always stick to this invokation scheme.

Regards,
Stuart