Date Subtraction

[rsutradhar_python]

How to subtract date which is stored in string variable?

Example:

date1="2006-01-10"
date2="2005-12-15"
date = date1 - date2
should give me 25 but problem is that date1 and date2 datatype is
string which need to be conerted into date fromat which i am not able
to do so please help me.

 

[Marc 'BlackJack' Rintsch]

How to subtract date which is stored in string variable?

Example:

date1="2006-01-10"
date2="2005-12-15"
date = date1 - date2
should give me 25 but problem is that date1 and date2 datatype is
string which need to be conerted into date fromat which i am not able
to do so please help me.

from datetime import date

date_str_1 = '2006-01-10'
date_str_2 = '2005-12-15'
date_1 = date(*map(int, date_str_1.split('-')))
date_2 = date(*map(int, date_str_2.split('-')))
print (date_1 - date_2).days - 1

Ciao,
Marc 'BlackJack' Rintsch

 

[Cameron Laird]

from datetime import date

date_str_1 = '2006-01-10'
date_str_2 = '2005-12-15'
date_1 = date(*map(int, date_str_1.split('-')))
date_2 = date(*map(int, date_str_2.split('-')))
print (date_1 - date_2).days - 1

.
.
.
Apparently you understand the original poster better than I.
What's with the "- 1"? If I read you correctly, you'd calculate
that there are zero days between, for example,
2006-01-13
and
2006-01-12
Do I have that right?

 

[Marc 'BlackJack' Rintsch]

.
.
.
Apparently you understand the original poster better than I.
What's with the "- 1"? If I read you correctly, you'd calculate
that there are zero days between, for example,
2006-01-13
and
2006-01-12
Do I have that right?

No that's not what I would calculate. I would do without the ``- 1`` but
the OP wanted 25 as result. Without the substraction it's 26. ;-)

Ciao,
Marc 'BlackJack' Rintsch