Datetime question

[Lad]

In a datetime object I would like to change days and hours.
Or in other words, I would like to copy this datetime object but
increase days and hours.
Is it possible?
For example:If I have a datetime object like this
datetime.datetime(2006, 8, 3, 14, 13, 56, 609000)

I would like to make a new ,for example like this

datetime.datetime(2006, 8, 12, 10, 13, 56, 609000)

is it possible to do so?
Thank you
L

 

[Marc 'BlackJack' Rintsch]

In a datetime object I would like to change days and hours.
Or in other words, I would like to copy this datetime object but
increase days and hours.
Is it possible?
For example:If I have a datetime object like this
datetime.datetime(2006, 8, 3, 14, 13, 56, 609000)

I would like to make a new ,for example like this

datetime.datetime(2006, 8, 12, 10, 13, 56, 609000)

is it possible to do so?

Yes it is, just add a `timedelta` object:

In [18]: a = datetime.datetime(2006, 8, 3, 14, 13, 56, 609000)

In [19]: a + datetime.timedelta(days=8, hours=20)
Out[19]: datetime.datetime(2006, 8, 12, 10, 13, 56, 609000)

Ciao,
Marc 'BlackJack' Rintsch

 

[Diez B. Roggisch]

In a datetime object I would like to change days and hours.
Or in other words, I would like to copy this datetime object but
increase days and hours.
Is it possible?
For example:If I have a datetime object like this
datetime.datetime(2006, 8, 3, 14, 13, 56, 609000)

I would like to make a new ,for example like this

datetime.datetime(2006, 8, 12, 10, 13, 56, 609000)

is it possible to do so?

you'd been pointed to the resources yesterday - please read manuals
carefully!

a = datetime.datetime(2006, 8, 12, 10, 13, 56, 609000)
b = a + datetime.timedelta(days=-2, hours=-4)


Diez

 

[Simon Brunning]

But wont this create a new object? Whereas if you want to modify the same
object, should we not be using replace? Or does it not matter in the global
picture?

datetime objects are immutable. You can't change the value of an
existing datetime object, only create a new one.

 

[Simon Brunning]

Just curious why when
I call id(a) I get the same id after I call the replace method.

In your example, you called a's replace() method, but did nothing with
the new datetime object that it returned. The original object, a,
naturally still has the same ID, but it also still has the same value.