datetime.timedelta.replace?

[Skip Montanaro]

Datetime objects have a replace method, but timedelta objects don't.
If I take the diff of two datetimes and want to zero out the
microseconds field, is there some way to do it more cleanly than this?

delta = dt1 - dt2
zero_delta = datetime.timedelta(days=delta.days, seconds=delta.seconds)

I guess that's not bad, but replace() seems cleaner (or at least more
congruent with datetime objects).

Skip