Determining caller's file and line number

[David Abrahams]

Is there any way to determine the file and line number (if any) of a
method's invocation from within its body?

Many Thanks in advance,

Dave

 

[Jean Brouwers]

Here is one example:

<pre>

from traceback import extract_stack as tb_extract_stack,

def caller(up=0):
'''Get file name, line number, function name and
source text of the caller's caller as 4-tuple:
(file, line, func, text).

The optional argument 'up' allows retrieval of
a caller further back up into the call stack.

Note, the source text may be None and function
name may be '?' in the returned result. In
Python 2.3+ the file name may be an absolute
path.
'''
try: # just get a few frames
f = tb_extract_stack(limit=up+2)
if f:
return f[0]
except:
pass
# running with psyco?
return ('', 0, '', None)

</pre>

/Jean Brouwers
ProphICy Semiconductor, Inc.

 

[David Abrahams]

Here is one example:

Fantastic! Thank you so much!