Dictionary invalid token error

[brad]

This works:

This does not (one the end, 09 is used instead of 9)
File "<stdin>", line 1
area_group = {001:06, 002:04, 003:04, 006:09}
SyntaxError: invalid token

Why does 09 cause an invalid token while 9 does not?

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Python 2.4.4 (#2, Apr 5 2007, 18:43:10)
[GCC 4.1.2 20061115 (prerelease) (Debian AMD64 4.1.1-21)] on linux2

 

[Richard Brodie]

Why does 09 cause an invalid token while 9 does not?

9 isn't a valid octal digit. You probably want to use strings for
storing telephone number like codes, if leading zeroes are
significant.

 

[brad]

Numbers with leading zeros are parsed as octal. 8 and 9 are invalid
digits in octal. Thus, it falls over. 00 through 07 will work fine,
but 08 and 09 will go kaput.

http://docs.python.org/ref/integers.html

-tkc

Thanks... that makes sense. I'll store them as strings.

 

[Tim Chase]

This works:

This does not (one the end, 09 is used instead of 9)

File "<stdin>", line 1
area_group = {001:06, 002:04, 003:04, 006:09}
SyntaxError: invalid token

Why does 09 cause an invalid token while 9 does not?

Numbers with leading zeros are parsed as octal. 8 and 9 are
invalid digits in octal. Thus, it falls over. 00 through 07
will work fine, but 08 and 09 will go kaput.

http://docs.python.org/ref/integers.html

-tkc