Dividing a number into individual digits

[Timothy Baron]

Here's a simple question: What's an effecient way to get the digits of
a number. For instance, if I have the number 37, how can I get "3" and
"7"?

 

[Edmond Kachale]

Here's a simple question: What's an effecient way to get the digits of
a number. For instance, if I have the number 37, how can I get "3" and
"7"?

I'm not sure about the efficiency but this can do:
number.to_s.split(//)
Ex: 1464002.to_s.split(//) =3D> ["1", "4", "6", "4", "0", "0", "2"]

Otherwise, you may need to derive a method of your own.


---
Edmond
Software Developer | Baobab Health Trust (http://www.baobabhealth.org/) |
Malawi

Cell: +265 999 465 137 | +265 881 234 717

*"Many people doubt open source software and probably don=92t realize that
there is an alternative=85 which is just as good.." -- Kevin Scannell*

 

[Robert Klemme]

Here's a simple question: =A0What's an effecient way to get the digits of
a number. =A0For instance, if I have the number 37, how can I get "3" and
"7"?

Five days ago the exact same question was raised here - and answered.
What prevented you finding that thread?

Cheers

robert


--=20
remember.guy do |as, often| as.you_can - without end
http://blog.rubybestpractices.com/

 

[Timothy Baron]

Five days ago the exact same question was raised here - and answered.
What prevented you finding that thread?

Cheers

robert

An inability to use the right search phrase? I had looked, but nothing
relevant came up. Thanks for letting me know about this other thread,
though. Just found it, and it answers the question nicely.

 

[(r.*n){2}]

An inability to use the right search phrase?  I had looked, but nothing
relevant came up.  Thanks for letting me know about this other thread,
though.  Just found it, and it answers the question nicely.

One alternative to split could be unpack

s = "12345" * 2000

s.unpack('C*').each {|d| printf("%c\n", d)}

note that s contains ascii values for each digit obtained ( '0' =>
48, ..., '9' => 57 )