Does Pygoogle allows for advanced search options?

[neocortex]

Hello All,
Can anyone help me with the Pygoogle:
from pygoogle import pygoogle
word = u'something'
request_word = word.encode('utf-8')
request = ('%s+site:.edu' % request_word)
g = pygoogle(request)
g.get_result_count()

Now, I realized that domain restriction works (site:.edu etc.), but I
would like to be able to control for language too. Is that possible
with the Pygoogle? If not, how can I make that happen?

Thanks!
PM

 

[Chris Rebert]

Hello All,
Can anyone help me with the Pygoogle:
from pygoogle import pygoogle

You're apparently talking about http://code.google.com/p/pygoogle/
rather than http://pygoogle.sourceforge.net/ ; the former appears to
have "borrowed" the latter's name without permission. Oi!

word = u'something'
request_word = word.encode('utf-8')
request = ('%s+site:.edu' % request_word)
g = pygoogle(request)
g.get_result_count()

Now, I realized that domain restriction works (site:.edu etc.), but I
would like to be able to control for language too. Is that possible
with the Pygoogle? If not, how can I make that happen?

The library doesn't seem to have built-in support for filtering by
language (and Google lacks a search query-string-based operator for
that), but it looks like you could implement that feature by adding an
"lr" parameter with an appropriate value to the query `args`
dictionary. See the "lr?" entry under "Web Search Specific Arguments"
on http://code.google.com/apis/websearch/docs/reference.html , and
lines 68 & 102 of pygoogle.py.

Cheers,
Chris

 

[neocortex]

The library doesn't seem to have built-in support for filtering by

language (and Google lacks a search query-string-based operator for
that), but it looks like you could implement that feature by adding an
"lr" parameter with an appropriate value to the query `args`
dictionary. See the "lr?" entry under "Web Search Specific Arguments"
onhttp://code.google.com/apis/websearch/docs/reference.html, and
lines 68 & 102 of pygoogle.py.

From those lines, it can be concluded that lr=lang_?? is not
supported, unfortunately. And, when I execute, I get an error.
Is there any other way to get Google search from Python? I really need
only number of hits.

Best,
PM

 

[Chris Rebert]

From those lines, it can be concluded that lr=lang_?? is not
supported, unfortunately.

Right; that's why I said "you could implement that feature". Pretty
easily it would seem.

And, when I execute, I get an error.

What exactly are you executing, and what's the exact error? Vagueness
is the enemy of debugging.

Regards,
Chris

 

[Petar Milin]

Right; that's why I said "you could implement that feature". Pretty
easily it would seem.

Thanks for believing in me ( ;-) ), but I am a newbie in Python world,
although with some experience in other prog. languages.
So, if I read pygoogle.py well, I sould add lr parameter in init and
then after lines 68 and 102?

Thanks again! You guys here are very kind and helpful!
Best,
Petar

 

[Stefan Sonnenberg-Carstens]

Am 21.11.2010 11:01, schrieb Petar Milin:

Thanks for believing in me ( ;-) ), but I am a newbie in Python world,
although with some experience in other prog. languages.
So, if I read pygoogle.py well, I sould add lr parameter in init and
then after lines 68 and 102?

Correct.
I just did not read source code enough to realize the parameter is needed
twice. You just could hack that out, too
Normally (what is normal, anyway ?) it's good practice to create an
contructor (__init__) in python which has the most common options
as keyword arguments and default values assigned, like so:

class Foo:
def __init__(self,lr='lang_en',url='http://some.of.this'):
self.lr = lr
self.url = url
...