Does this program produce undefined behavior?

[Chris M. Thomasson]

I was wondering if there are any "gotchas" wrt using member pointers to
implement a intrusive linked-list:
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#include <cstddef>
#include <cassert>
#include <iostream>




template<typename T>
struct slink
{
T* m_next;
};




template<typename T, slink<T> T::*T_link>
class sl_iter
{
T* m_cur;


public:
sl_iter(T* cur) : m_cur(cur) { }


T* operator ->()
{
assert(m_cur);
return m_cur;
}


T* get()
{
return m_cur;
}


bool end()
{
return (! m_cur) ? true : false;
}


sl_iter& operator ++()
{
m_cur = (m_cur) ? (m_cur->*T_link).m_next : NULL;
return *this;
}
};




template<typename T, slink<T> T::*T_link>
class slist
{
T* m_head;


public:
typedef sl_iter<T, T_link> sl_iter_type;

slist(T* head = NULL) : m_head(head) {}


public:
T* head()
{
return m_head;
}


void push(T* object)
{
(object->*T_link).m_next = m_head;
m_head = object;
}


T* pop()
{
T* head = m_head;
if (head) m_head = (head->*T_link).m_next;
return head;
}
};




struct foo
{
typedef slink<foo> slink_type;

unsigned m_id;
slink_type m_slink1;
slink_type m_slink2;

typedef slist<foo, &foo::m_slink1> slist1_type;
typedef slist<foo, &foo::m_slink2> slist2_type;
};




int
main()
{
{
foo f1, f2, f3;

f1.m_id = 1; f2.m_id = 2; f3.m_id = 3;

foo::slist1_type sl1;
foo::slist2_type sl2;

sl1.push(&f1);
sl1.push(&f2);
sl1.push(&f3);

sl2.push(&f3);
sl2.push(&f2);
sl2.push(&f1);

for (foo::slist1_type::sl_iter_type i(sl1.head());
! i.end();
++i)
{
std::cout << "("
<< i.get()
<< ")->foo("
<< i->m_id << ")"
<< std::endl;
}

for (foo::slist2_type::sl_iter_type i(sl2.head());
! i.end();
++i)
{
std::cout << "("
<< i.get()
<< ")->foo("
<< i->m_id << ")"
<< std::endl;
}
}

return 0;
}
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AFAICT, everything should be Kosher.