Ending Function on Error then Continue in main()

[- Steve -]

I have a situtation where if a overloaded operator is used incorrectly I
need it to cout some info to the screen, end the function it was called in,
and continue on in main. How on earth do you do that?

The exact example can be found at http://planetevans.com/c under test 17,
18, and 19.

One of the specific examples is

test17()
{
cout << "17. Array declared with illegal array bounds: IntArray f(5,
2);" << endl << endl;
IntArray f(5, 2); //illegal becuase it is trying to define an
array with an index going from 5 to 2. The constructor is show below
for(int i = f.low(); i <= f.high(); ++i) //dont want this to run
f = i * 10; //dont want this to run
cout << f << endl; //dont want this to run
}

IntArray::IntArray(int low, int high)
{
arrayLow=low; //start of array index
arrayHigh=high; //end of array index
if(arrayHigh>=arrayLow)
array=new int[arrayHigh-arrayLow+1]; //create array memory
locations
else
cout << "Low Array Boundry Higher than High Array Boundry" << endl;
//now I need to end the function that this was called from
}

 

[- Steve -]

: I have a situtation where if a overloaded operator is used incorrectly I
: need it to cout some info to the screen, end the function it was called
in,
: and continue on in main. How on earth do you do that?
use again in other programs. Report them to the calling program and let the
program (and >>its programmer) decide how to handle them. That's what
exceptions have been invented for. Have a look at try/catch/throw and
std::exception.

Unfortantley it's a requirment for the assignment I've been given.

 

[Karl Heinz Buchegger]

test17()
{
cout << "17. Array declared with illegal array bounds: IntArray f(5,
2);" << endl << endl;
IntArray f(5, 2); //illegal becuase it is trying to define an
array with an index going from 5 to 2. The constructor is show below
for(int i = f.low(); i <= f.high(); ++i) //dont want this to run
f = i * 10; //dont want this to run
cout << f << endl; //dont want this to run
}

IntArray::IntArray(int low, int high)
{
arrayLow=low; //start of array index
arrayHigh=high; //end of array index
if(arrayHigh>=arrayLow)
array=new int[arrayHigh-arrayLow+1]; //create array memory
locations
else
cout << "Low Array Boundry Higher than High Array Boundry" << endl;
//now I need to end the function that this was called from
}

As Heinz has already told you: you could throw an exception in the constructor.
Another possibility would be:

class IntArray
{
public:
IntArray( int LowBound, int HighBound );

bool IsGood();

...
};

void test17()
{
IntArray f( 5, 2 );

if( !f.IsGood() )
return;

...
}

 

[Simon Turner]

"- Steve -"
: I have a situtation where if a overloaded operator is used
: incorrectly I need it to cout some info to the screen, end the
: function it was called in, and continue on in main. How on earth do
: you do that?


Unfortantley it's a requirment for the assignment I've been given.

The "Avoid reporting errors on the screen..." is a recommendation that
you should avoid it in general. If you need to do it here, then do it.

The advice on using exceptions is orthogonal, and is what you need.
Note that it isn't an overloaded operator you're using incorrectly, but
the constructor. Anyway, your code should probably look like:

#include <stdexcept>

class IntArray
{
public:
IntArray(int low, int high)
{
if( low > high )
// add output here if you need it
throw std::range_error("IntArray: low > high");

//...your code...
}
};

void test17()
{
IntArray f(5,2); //this will throw straight away

//...this code will not be reached...
}

int main()
{
try {
//...
test17();
//...

} catch( std::exception& ex ) {
// we come straight here after IntArray::IntArray
// throws std::runtime_error, skipping the rest of
// test17().
}
}