error: ISO C++ forbids cast to non-reference type used as lvalue

[danny van elsen]

hello all,

I have recently changed from gcc 3.3.1 to version 3.4.3.

In the following code

class MyClass
{
...
private:
void * current;
}

void *
MyClass::Use_Pool(long size)
{
void * temp;

////////////////////////////////////////////////////////////////////////////

temp = current;
(char*) current += size;
}

I now have the following error:

memory_pool.cc:69: error: ISO C++ forbids cast to non-reference type used as lvalue


what would be the best way to solve this?

thanks, D.

 

[Victor Bazarov]

I have recently changed from gcc 3.3.1 to version 3.4.3.

In the following code

class MyClass
{
...
private:
void * current;
}

void *
MyClass::Use_Pool(long size)
{
void * temp;

////////////////////////////////////////////////////////////////////////////

temp = current;
(char*) current += size;
}

I now have the following error:

memory_pool.cc:69: error: ISO C++ forbids cast to non-reference type used as lvalue


what would be the best way to solve this?

Why don't you declare 'current' to be 'char*' to begin with?

V

 

[Pete Becker]

(char*) current += size;

If Victor's solution isn't acceptable (although it almost certainly
should be):

*(char**)current += size;

 

[Victor Bazarov]

If Victor's solution isn't acceptable (although it almost certainly
should be):

*(char**)current += size;

Or

(char*&)current += size;

V

 

[Heinz Ozwirk]

If Victor's solution isn't acceptable (although it almost certainly
should be):

*(char**)current += size;

Are you sure? Shouldn't that be

*(char**)&current += size;

or
(char*&)current += size;

Heinz

 

[Pete Becker]

Are you sure? Shouldn't that be

*(char**)&current += size;

I'm sure.

 

[Pete Becker]

I'm sure.

However, being sure isn't necessarily the same as being right. <g>
You're right: you need the &.