escape sequence in string

[Jim Langston]

I want to build a string that contains the character 1, followed by ABC
followed by the characters 255 255. One would think it would be simple:

std::string Data( "\x01ABC\xFF\xFF", 6);
but that doesn't compile. It says:
error C2022: '6844' : too big for character

At first I wondered where the heck it got 6844 then I realized. It took the
excape sequence as \x01ABC since A, B and C are valid hexidecimal digits.
So I tried
std::string Data( "\x0001ABC\xFF\xFF" );
but same error. How do I get the compiler to stop treating characters as
hex digits but part of the data? I know I could break up the string
something like:
std::string Data("\x01", 1 );
Data += "ABC\xFF\xFF";
but that seems like an extra step I really don't need (or do I)?

 

[ondra.holub]

There is no limit, how many hex characters should be considered. But
you can deal with it this way:

std::string s("\x1" "ABC");

 

[terminator]

I want to build a string that contains the character 1, followed by ABC
followed by the characters 255 255. One would think it would be simple:

std::string Data( "\x01ABC\xFF\xFF", 6);
but that doesn't compile. It says:
error C2022: '6844' : too big for character

At first I wondered where the heck it got 6844 then I realized. It took the
excape sequence as \x01ABC since A, B and C are valid hexidecimal digits.
So I tried
std::string Data( "\x0001ABC\xFF\xFF" );
but same error. How do I get the compiler to stop treating characters as
hex digits but part of the data? I know I could break up the string
something like:
std::string Data("\x01", 1 );
Data += "ABC\xFF\xFF";
but that seems like an extra step I really don't need (or do I)?

try this:
"str1""str2""str3"
compiler automatically concates the 3 strings into 1 at compile time

 

[BobR]

Jim Langston wrote in message ...

I want to build a string that contains the character 1, followed by ABC
followed by the characters 255 255. One would think it would be simple:

std::string Data( "\x01ABC\xFF\xFF", 6);
but that doesn't compile. It says:
error C2022: '6844' : too big for character

At first I wondered where the heck it got 6844 then I realized. It took the
excape sequence as \x01ABC since A, B and C are valid hexidecimal digits.
So I tried
std::string Data( "\x0001ABC\xFF\xFF" );
but same error. How do I get the compiler to stop treating characters as
hex digits but part of the data? I know I could break up the string
something like:
std::string Data("\x01", 1 );
Data += "ABC\xFF\xFF";
but that seems like an extra step I really don't need (or do I)?

(answered already, but...) Don't forget:

std::string Chars;
Chars.push_back( char( 01 ) );
Chars.push_back( char( 'A' ) );
Chars.push_back( char( 254 ) );
Chars.push_back( char( 255 ) );
Chars.push_back( char( 0xFF ) );
Chars.at( 2 ) = char( 0x0C );

.... just in case you need it.

 

[Jim Langston]

Jim Langston wrote in message ...


(answered already, but...) Don't forget:

std::string Chars;
Chars.push_back( char( 01 ) );
Chars.push_back( char( 'A' ) );
Chars.push_back( char( 254 ) );
Chars.push_back( char( 255 ) );
Chars.push_back( char( 0xFF ) );
Chars.at( 2 ) = char( 0x0C );

... just in case you need it.

Thanks, yeah, knew about that.