E
Erik S. Bartul
as i understand if, the first argument of execlp() is a null terminated
string containing the path of the command which to be executed.
the second argument is an array of pointers to null terminated strings,
containing the arguments to be passed to said command, ending in a null
pointer.
my question is, what does the third argument do?
string containing the path of the command which to be executed.
the second argument is an array of pointers to null terminated strings,
containing the arguments to be passed to said command, ending in a null
pointer.
my question is, what does the third argument do?