executing a function with feeding its global variables

[Jean-Daniel]

Hello,

I am writing a small framework where the user which writes a function
can expect some global variable to be set in the function namespace.

The user has to write a function like this:
"""
# function.py
from framework import, command, run

@command
def myfunc():
print HOST

if __name__=="__main__":
run()
"""

command() registers the function, and run() evaluates or execute the
function within an environment or a namespace where HOST has been
automagically set.

Question: how can write run in a way that when using run() in a
script, the decorated function will be run with the special names made
available?

Here is the code for this, which does not work as intended because the
'HOST' can not be found when evaluating the decorated function

"""
# framework.py
HOST = '192.168.0.1'
PORT = 12345

commands = []

def command(f):
commands.append(f)
return f

def run():
for f in commands:
assert globals()['HOST']
exec 'f()' in globals(),locals()

if __name__=='__main__':

@command
def info():
print HOST,PORT

run()
"""

Note that the assert makes sure the HOST variable is indeed present in
the globals when running the function. When running function.py, I get
an NameError exception. When I put the func function in the framework
module and execute framework.py as a script, this works fine, the
global HOST is available in the func namespace which gets printed. I
tried many combinations of eval() or exec as well as many combinations
for the globals() and locals() mapping fed to eval/exec without
success.


Thank you for your help

 

[Peter Otten]

Hello,

I am writing a small framework where the user which writes a function
can expect some global variable to be set in the function namespace.

The user has to write a function like this:
"""
# function.py
from framework import, command, run

@command
def myfunc():
print HOST

if __name__=="__main__":
run()
"""

command() registers the function, and run() evaluates or execute the
function within an environment or a namespace where HOST has been
automagically set.

Question: how can write run in a way that when using run() in a
script, the decorated function will be run with the special names made
available?

Here is the code for this, which does not work as intended because the
'HOST' can not be found when evaluating the decorated function

"""
# framework.py
HOST = '192.168.0.1'
PORT = 12345

commands = []

def command(f):
commands.append(f)
return f

def run():
for f in commands:
assert globals()['HOST']
exec 'f()' in globals(),locals()

if __name__=='__main__':

@command
def info():
print HOST,PORT

run()
"""

Note that the assert makes sure the HOST variable is indeed present in
the globals when running the function. When running function.py, I get
an NameError exception. When I put the func function in the framework
module and execute framework.py as a script, this works fine, the
global HOST is available in the func namespace which gets printed. I
tried many combinations of eval() or exec as well as many combinations
for the globals() and locals() mapping fed to eval/exec without
success.

Every module has its own global namespace, and a function is looking for
global variables in the namespace it is defined in, not the one where the
function is called from. A function defined in Python carries its global
namespace with it as the __globals__ attribute (func_globals in older Python
versions).

def run():
for f in commands:
f.__globals__.update(HOST=HOST, PORT=PORT)
f()

Note that every function in the function's module will see the extra
variables.

Peter

 

[Jean-Daniel]

Hello,

I am writing a small framework where the user which writes a function
can expect some global variable to be set in the function namespace.

The user has to write a function like this:
"""
# function.py
from framework import, command, run

@command
def myfunc():
    print HOST

if __name__=="__main__":
    run()
"""

command() registers the function, and run() evaluates or execute the
function within an environment or a namespace where HOST has been
automagically set.

Question: how can write run in a way that when using run() in a
script, the decorated function will be run with the special names made
available?

Here is the code for this, which does not work as intended because the
'HOST' can not be found when evaluating the decorated function

"""
# framework.py
HOST = '192.168.0.1'
PORT = 12345

commands = []

def command(f):
    commands.append(f)
    return f

def run():
    for f in commands:
        assert globals()['HOST']
        exec 'f()' in globals(),locals()

if __name__=='__main__':

    @command
    def info():
        print HOST,PORT

    run()
"""

Note that the assert makes sure the HOST variable is indeed present in
the globals when running the function. When running function.py, I get
an NameError exception. When I put the func function in the framework
module and execute framework.py as a script, this works fine, the
global HOST is available in the func namespace which gets printed. I
tried many combinations of eval() or exec as well as many combinations
for the globals() and locals() mapping fed to eval/exec without
success.

Every module has its own global namespace, and a function is looking for
global variables in the namespace it is defined in, not the one where the
function is called from. A function defined in Python carries its global
namespace with it as the __globals__ attribute (func_globals in older Python
versions).

def run():
   for f in commands:
       f.__globals__.update(HOST=HOST, PORT=PORT)
       f()

Note that every function in the function's module will see the extra
variables.

Cool, thanks.

I read here: http://docs.python.org/reference/datamodel.html about the
func_globals and how it is a read only attribute. I incorrectly
thought that this dictionary was read only because the reference was
read only.