# Expected Value

Discussion in 'Python' started by George, Sep 9, 2005.

1. ### GeorgeGuest

I have never done any programming with python in my life so I will most
definetly need help understanding how I can accomplish this part of my
program.

The function expectP(z) computes E(X) for the random variable
representing a sample over the probability generated by "pf" for the
set of discrete items [1,100000]. The constant c is needed so that the
probability sum to 1.0, as required by the definition of probability.
The function pf(r,c,x) returns the probability that item x will be
equal to a randomly chosen variable, denoted by P(x) or P(X=x) in
mathematical texts, where c is the constant mentioned above and r is
needed because we are considering a power law distribution. I need help
in writing the expectP function and do I compile and execute this code
on a linux box.

"""
Module to compute expected value.

>>> showExpectP(0.5)

33410
>>> showExpectP(0.85)

15578
>>> showExpectP(0.9)

12953
>>> showExpectP(0.99)

8693
>>> showExpectP(0.999)

8312

"""

def norm(r):
"calculate normalization factor for a given exponent"
# the function for this distribution is P(x) = c*(x**-r)
# and the job of this norm function is to calculate c based
# on the range [1,10**5]
sum = 0.0
for i in range(1,1+10**5):
# final sum would be more accurate by summing from small values
# to large ones, but this is just a homework, so sum 1,2,..10**5
sum += float(i)**-r
return 1.0/sum

def pf(r,c,x):
"return a power-law probability for a given value"
# the function for this distribution is P(x) = c*(x**-r)
# where the constant c is such that it normalizes the distribution
return c*(float(x)**-r)

#--------- between these lines, define expectP() function
-----------------

#--------- end of expectP() definition
------------------------------------

def showExpectP(limit):
"display ExpectP(limit) by rounding down to nearest integer"
k = expectP(limit)
return int(k)

if __name__ == '__main__':
import doctest, sys
doctest.testmod(sys.modules[__name__])

thankyou sooo much.

George, Sep 9, 2005