Explaination of conditional operators

[richie05 bal]

wondering if somebody can explain how this works.

1. bool result = (!a || b <= 0) && (!c || d <=0);

2. int b = (x >0) ;

if somebody could point to some tutorial that would be great too.

Thanks in advance.

 

[red floyd]

wondering if somebody can explain how this works.

1. bool result = (!a || b <= 0) && (!c || d <=0);

2. int b = (x >0) ;

if somebody could point to some tutorial that would be great too.

Thanks in advance.

What does your textbook say about how to evaulate boolean expressions?

 

[Fred Zwarts]

wondering if somebody can explain how this works.

1. bool result = (!a || b <= 0) && (!c || d <=0);

2. int b = (x >0) ;

if somebody could point to some tutorial that would be great too.

Thanks in advance.

The answer depends on the types of a, b, c, d and y.
How it works? The compiler will use the operators that are defined for these types.
These operators return a value which also has a type.
Depending on the resulting type, another operator that is defined for this type is used,
until the whole expression is evaluated.
If an operator is not found for a type, or when it is ambiguous, the compiler will emit a message.
To find the order of the evaluation of the subexpressions,
read your textbook about precedence of operators.