expression evaluation order

[n.torrey.pines]

It's my understanding that the standard guarantees that h() returns 10
here because of the "sequence points". Is this right?

int f(int& i) { i += 1; return 1; }

int g(int& i) { i += 2; return 2; }

int h() {
int x = 0;
int y = f(x) + g(x) + g(x);
return x+y;
}

 

[Alf P. Steinbach]

* (e-mail address removed):

It's my understanding that the standard guarantees that h() returns 10
here because of the "sequence points". Is this right?

No, the order of evaluation does not matter here.

int f(int& i) { i += 1; return 1; }

int g(int& i) { i += 2; return 2; }

int h() {
int x = 0;
int y = f(x) + g(x) + g(x);
return x+y;
}

Try to avoid side effects.

 

[Andrew Koenig]

* (e-mail address removed):

No, the order of evaluation does not matter here.

I think the point is that because f and g are functions, in the expression

f(x) + g(x) + g(x)

each function must be evaluated in its entirety before any other function is
evaluated. Moreover, there is a sequence point before each function is
called. Therefore, although it is indeterminate in what order the functions
are called, that fact doesn't matter because the result is the same
regardless of the order in which they are called.

On the other hand, the foregoing doesn't affect my opinion that the program
should be taken out and shot