file I/O and arithmetic calculation

[Keira Wilson]

Dear all,

I would appreciate if someone could write a simple python code for the
purpose below:

I have five text files each of 10 columns by 10 rows as follows:

file_one = 'C:/test/1.txt'
file_two = 'C:/test/2.txt' . . .
file_five = 'C:/test/5.txt'

I want to calculate the mean of first row (10 elements) for each file (5
files), if mean of first column (10 elements) of each file (5 files) is 50.

Thank you in advance.

Keira

 

[Denis McMahon]

I would appreciate if someone could write a simple python code for the
purpose below:

Didn't have your data, so couldn't verify it completely, but try this:

import re
def v(s):
l=len(s)
t=0.
for i in range(l):
t=t+(abs(ord(s))*1.)
return t/(l*1.)
for n in range(5):
m="c:/test/"+str(n+1)+".txt"
f=open(m,"r")
d=[]
t=0.
for l in range(10):
d=d+[re.findall(r"[0-9.eE+-]+",f.readline())]
t=t+v(d[l][0])
f.close()
c=t/10.
if c==50.:
t=0.
for u in range(10):
t=t+v(d[0])
r=t/10.
print "%s C1: %f R1: %f"%(m,c,r)

 

[Carlos Nepomuceno]

----------------------------------------

From: (e-mail address removed) [...]

import re
def v(s):
l=len(s)
t=0.
for i in range(l):
t=t+(abs(ord(s))*1.)
return t/(l*1.)
for n in range(5):
m="c:/test/"+str(n+1)+".txt"
f=open(m,"r")
d=[]
t=0.
for l in range(10):
d=d+[re.findall(r"[0-9.eE+-]+",f.readline())]
t=t+v(d[l][0])
f.close()
c=t/10.
if c==50.:
t=0.
for u in range(10):
t=t+v(d[0])
r=t/10.
print "%s C1: %f R1: %f"%(m,c,r)

Can you send it again without tabs?