friends, namespaces and operators.

[glen stark]

Hi.

I had an interesting experience with a brand x compiler recently. I had
class defined within a namespace, and in that class I declared the "<<"
operator as a friend to that class. Then, in the cpp code I implemented
the operator overloading within a "using namespace" context, only to get
access errers. To get it to work I had to put a namespaceName:: in
front of the operator keyword...

for your edification, here is a sample code:
================
HEADER FILE

#include <string>
#include <ostream>

namespace voxel{
class PrivateClass{
public:
PrivateClass():info("hiya"){};
friend std:stream& operator<<(std:stream&, const PrivateClass&);
private:
std::string info;
};
}
===================
CPP FILE

#include "stdafx.h"
#include "PrivateClass.h"
using namespace voxel;
std:stream& voxel:perator<<(std:stream& os, const PrivateClass& pc)
{
os<<pc.info;
return os;
}

int main(int argc, char* argv[])
{

PrivateClass pc;
std::cout<<pc;
return 0;

}


=====end of code

So my question is: is this a compiler bug, or is this a loophole in the
standard somehow? If it's a compiler bug, does the standard imply that
it should behave as i would think, or what? I would very much like any
clarification you can offer me.

 

[Joona I Palaste]

Hi.

I had an interesting experience with a brand x compiler recently. I had
class defined within a namespace, and in that class I declared the "<<"

comp.lang.c++ is that way =============================================>

 

[glen stark]

comp.lang.c++ is that way =============================================>

oops, so sorry, clicked on the wrong group...

 

[Martin Ambuhl]

Hi.

I had an interesting experience with a brand x compiler recently. I had
class defined within a namespace, and in that class I declared the "<<"
operator as a friend to that class. [etc.]

Please direct your questions about C++, a different language from C, to
news:comp.lang.c++