Function as parameter of a function with parameters

[marc]

Hello,

I can do :

void DoFunct(void (*funcp)());

void MyFunct()
{
//...
}

DoFunct(MyFunct);

but is it possible to pass to DoFunct() a function MyFunct with
parameters ?

Thanks in advance.

 

[James Kuyper]

Hello,

I can do :

void DoFunct(void (*funcp)());

void MyFunct()
{
//...
}

DoFunct(MyFunct);

but is it possible to pass to DoFunct() a function MyFunct with
parameters ?

Thanks in advance.

void DoFunct(void(*funcp)(int));

void MyFunct(int i)
{
// ...
}

int main(void)
{
DoFunct(MyFunct);
// ...
}

 

[marc]

int main(void)
{
        DoFunct(MyFunct);

Thanks for your answer, but my problem is how can I pass and read the
parameters of MyFunct ?

DoFunct(MyFunct(1)); => doesn't compile.

And inside DoFunct, I'm not able to read the parameters :
This doesn't compile=>

void DoFunct(void(*funcp)(int i))
{
(*funcp)(i);
}

 

[marc]

void DoFunct(int i, void (*funcp)(int))

Thanks, the tip was indeed to pass the parameters distinctly.