Function.call and Function.apply

[HopfZ]

I would like to check if my understanding of the two functions are
correct.

Is this correct? The following three lines are equivalent, for
example, [1] can be replaced with [2] or [3] anywhere in a script
without changing the return value and without changing any side effect.


[1] var r = o.f(a,b);
[2] var r = o.f.call(o,a,b);
[3] var r = o.f.apply(o,[a,b]);

( o is an object and o.f is a function. )

The following three lines are equivalent:
[1'] var r = g(a,b);
[2'] var r = g.call(this,a,b);
[3'] var r = g.apply(this,[a,b]);

( g is a function, for example,
var g = function(a,b){return [this,a,b];}. )

 

[Lasse Reichstein Nielsen]

Is this correct? The following three lines are equivalent ....
[1] var r = o.f(a,b);
[2] var r = o.f.call(o,a,b);
[3] var r = o.f.apply(o,[a,b]); Correct


The following three lines are equivalent:
[1'] var r = g(a,b);
[2'] var r = g.call(this,a,b);
[3'] var r = g.apply(this,[a,b]);

Only if used where "this" refers to the global object (i.e., the call
is in the global scope or inside a function called in this way).

/L