Function call selection using ternary operator

[marco_segurini]

Hi,

I am wondering if there is a way to use the ternary operator to select
a function, between two, even if at least one of them is overloaded.
Ex:

void f1(int) {}
void f1(double) {}
void f2(int) {}
//void f2(double) {}

int main()
{
bool bTest = false;
(bTest ? f1 : f2)(int(1)); // this statement does not compile
return 0;
}

TIA.
Marco

 

[Sumit Rajan]

Hi,

I am wondering if there is a way to use the ternary operator to select
a function, between two, even if at least one of them is overloaded.
Ex:

void f1(int) {}
void f1(double) {}
void f2(int) {}
//void f2(double) {}

int main()
{
bool bTest = false;
(bTest ? f1 : f2)(int(1)); // this statement does not compile

bTest ? f1(int(1)) : f2(int(1));

Regards,
Sumit.

 

[marco_segurini]

bTest ? f1(int(1)) : f2(int(1));

Thanks for your reply Sumit.

This solution is the same as use:

if (bTest)
f1(1);
else
f2(1);

My goal is to avoid to repeat the actual parameters list (1).

Bye.
Marco.

 

[Richard Herring]

Thanks for your reply Sumit.

This solution is the same as use:

if (bTest)
f1(1);
else
f2(1);

My goal is to avoid to repeat the actual parameters list (1).

You need a typedef to disambiguate the pointer to the overloaded
function:.

typedef void (*FInt)(int);
typedef void (*FDouble)(double); // etc

(bTest ? FInt(f1) : FInt(f2)) (1);

 

[Dan Cernat]

Hi,

I am wondering if there is a way to use the ternary operator to select
a function, between two, even if at least one of them is overloaded.
Ex:

void f1(int) {}
void f1(double) {}
void f2(int) {}
//void f2(double) {}

int main()
{
bool bTest = false;
(bTest ? f1 : f2)(int(1)); // this statement does not compile
return 0;
}

TIA.
Marco

use function pointers:

void f1(int x)
{
}

void f2(int x)
{
}

int main()
{
bool bTest = true;

void (*f)(int x);

f = bTest ? f1 : f2;
f(3);

return 0;
}

Dan