Function resolution for temp object

[Mark Gilbert]

Can you explain this to me? If I make a variable of type ostringstream and
do << "str", I get what I want, but if I create a temporary object of the
same type, I get a different version of operator<<.

std:stringstream os;
// This calls :perator<<(ostream &, const char *)
os << "str";

// But, this calls ostringstream:perator<<(const void *)
std:stringstream() << "str";

I am using MSVC 2005, though I think the behavior was the same with MSVC
2003.

Thanks very much,
Mark Gilbert

 

[mlimber]

Can you explain this to me? If I make a variable of type ostringstream and
do << "str", I get what I want, but if I create a temporary object of the
same type, I get a different version of operator<<.

std:stringstream os;
// This calls :perator<<(ostream &, const char *)
os << "str";

// But, this calls ostringstream:perator<<(const void *)
std:stringstream() << "str";

I am using MSVC 2005, though I think the behavior was the same with MSVC
2003.

Thanks very much,
Mark Gilbert

Methinks it's because you cannot bind a temporary to a non-const
reference (as in the first parameter to operator<<(ostream &, const
char *) ).

Cheers! --M