g++ wrarning hides constructor

[husainap]

Hi,

I have code like this

file1.h
=======
typedef struct myStructName{
....
...
...
}MyStructName;

file2.h
=======
extern int myStructName (MyStructName *myName);


file3.c
======
#include "file1.h"
#include "file2.h"
.......
.......
.......


While compling with g++ I am getting warning like,
In file included from file3.c:line #:
file2.h :279: warning: `int myStructName (MyStructName *)' hides
constructor for `struct myStructName'

Is there any compile time option to hise this warning? or any other
solution to hide this warning

Thankns
Husain

 

[Karl Heinz Buchegger]

Is there any compile time option to hise this warning? or any other

solution to hide this warning

Use unique names ?

 

[Old Wolf]

Hi,

I have code like this

typedef struct myStructName{
}MyStructName;

extern int myStructName (MyStructName *myName);

While compling with g++ I am getting warning like,
file2.h :279: warning: `int myStructName (MyStructName *)' hides
constructor for `struct myStructName'

In case you didn't understand the error: "myStructName" is
a type name. Then you declare a function called "myStructName".
So you have a type and a function with the same name.
The warning is telling you that you now will not be able to
construct an object like:

myStructName s;

because the function name hides the type name.
(Of course, you can construct it using its alias "MyStructName",
or by specifying "struct myStructName").

Is there any compile time option to hise this warning? or any
other solution to hide this warning

IMHO the best thing to do is to stop using the same name
for a function and a type !

You should declare your struct as:

struct MyStructName
{
};

The typedef is just a waste of space (why declare 2 type names
when you only need one?)