generating infinit doubles

[MrPugh]

Hi!

I need to initialize a double with infinity (inf or 1.#INF). Now in
Windows you can do that by simply assigning it this way:

double x = numeric_limits<double>::infinity();

The problem is: on Unix-systems, that will return 0.0 .

Is there another way creating infinity besides division by zero (x =
1.0 / 0.0 would return the desired value, but not without a
warning...)?

Thanks in advance for the help.

Ruben

 

[Ron Natalie]

(a) This is the _standard_ way to get 'x' to be infinity.

And plenty of UNIX systems have infinity and do the right
thing. The fact that MrPugh's implementation doesn't isn't
a reflection on UNIX overall.

 

[Victor Bazarov]

And plenty of UNIX systems have infinity and do the right
thing. The fact that MrPugh's implementation doesn't isn't
a reflection on UNIX overall.

I didn't contest MrPugh's statement because I don't know UNIX
that well (although the generalisation didn't sound OK, to be
entirely honest). I'll trust your word on that.

 

[Ron Natalie]

I didn't contest MrPugh's statement because I don't know UNIX
that well (although the generalisation didn't sound OK, to be
entirely honest). I'll trust your word on that.

Of course, the other thing is that infinity() is returning the correct value
and his printf or whatever he's using to check it can't deal with it.