Getting return code for a Python script invoked from a Linux shellscript

[volcano]

Hi, folks,
I have a Python script that is invoked by a shell script. I uses
sys.exit() with a parameter within python.

The calling script is using this line to get the return code:
exit_code = !$

but it fails to get it. What's wrong here? (I am no Linux guru)

Thanks in advance
Mark

 

[Igor Pozgaj]

The calling script is using this line to get the return code: exit_code
= !$

but it fails to get it. What's wrong here? (I am no Linux guru)

Exit code is obtained with $?, not with !$

 

[Jeff McNeil]

Hi, folks,
I have a Python script that is invoked by a shell script. I uses
sys.exit() with a parameter within python.

The calling script is using this line to get the return code:
exit_code = !$

but it fails to get it. What's wrong here? (I am no Linux guru)

Thanks in advance
Mark

Assuming Bash, you'll want $? instead. The '!$' construct is used to
pull the last argument of the previous command. Also, if I remember
correctly, the history mechanism is disabled within shell scripts.

 

[Donn]

exit_code = !$

I think it's $? to get the code.
\d

 

[volcano]

On Wednesday 23 September 2009 18:51:29 volcano wrote:> exit_code = !$

I think it's $? to get the code.
\d

Thanks to all who replied,
actually, it was $! ( brain 'copy-paste' failure ) and $? did the
job!!!