going from c to c++

[nimeshmaheshwari]

Hi

I need some help, in syntax, going from c to c++

how will the following syntax be written in c++ using the new statement

if ((new_table->table = malloc(sizeof(list_t *) * size)) == NULL) {
return NULL;

here are the struct definitions

struct createList
{
int data;
createList *list;
};

struct createTable
{
int table_size;
createList **table;
};

new_table is an instance of createTable.

Any help will be appreciated

thanks

nimesh

 

[Pavel Shved]

I need some help, in syntax, going from c to c++

One of the main misleadings in going from C to C++ is thinking that
they differ by syntax only :-D.
Feel free to use malloc in C-like code -- there is absolutely no sence
in new statement in your code. Or use classes like std::list ot
std::vector instead.

 

[Ondra Holub]

(e-mail address removed) napsal:

Hi

I need some help, in syntax, going from c to c++

how will the following syntax be written in c++ using the new statement

if ((new_table->table = malloc(sizeof(list_t *) * size)) == NULL) {
return NULL;

here are the struct definitions

struct createList
{
int data;
createList *list;
};

struct createTable
{
int table_size;
createList **table;
};

new_table is an instance of createTable.

Any help will be appreciated

thanks

nimesh

If you are compiling code whic uses malloc with C++ compiler, you have
to typecast result of malloc to correct type, because malloc returns
void*. You do not need to do anything else (in this case).

 

[Rolf Magnus]

Hi

I need some help, in syntax, going from c to c++

how will the following syntax be written in c++ using the new statement

if ((new_table->table = malloc(sizeof(list_t *) * size)) == NULL) {
return NULL;

new_table->table = new createList*[size];

A null pointer check is not needed, since operator new never returns a null
pointer. It throws an exception if it can't allocate.