E
Emmanuel Oga
A better way to do this? :
arr= [1, 2, 3, 4, 5, 6, 7, 8]
new= []
while !arr.empty?
elem1, elem2= arr.pop, arr.pop
new << [elem2, elem1];
end
new.reverse!
new= [[1, 2], [3, 4], [5, 6], [7, 8]]
Thanks!
arr= [1, 2, 3, 4, 5, 6, 7, 8]
new= []
while !arr.empty?
elem1, elem2= arr.pop, arr.pop
new << [elem2, elem1];
end
new.reverse!
new= [[1, 2], [3, 4], [5, 6], [7, 8]]
Thanks!