Help with a HTTP GET request

Paul Hemans · May 13, 2009

I am trying to build a HTTP request that looks like:
http://localhost/common/foxisapi.dll/tmsmail.x2.isapi?<PROCESS%20sync=''%20schema=''%20class='replicateApplication.getChanges'%20/>
Works in a browser.

lxml.parse() gives me:
failed to load external entity

urllib2.urlopen() gives me:
Bad request

So I am trying httplib I have encoded the GET request with urllib.quote
()
and now I am attempting to use HTTPConnection

%3CPROCESS%20sync%3D%27%27%20schema%3D%27%27%20class%3D
%27replicateApplication.getChanges%27%20/%3E

<html><head><title>Error</title></head><body>The parameter is
incorrect.
</body></html>

Any help would be appreciated.

Chris Rebert · May 13, 2009

I am trying to build a HTTP request that looks like:
http://localhost/common/foxisapi.dll/tmsmail.x2.isapi?<PROCESS%20sync=''%20schema=''%20class='replicateApplication.getChanges'%20/>
Works in a browser.

I'm not 100% sure, but I don't think you can have < or > in a URL.
Your browser might be implicitly encoding them for you somehow.

Cheers,
Chris

Tim Harig · May 13, 2009

http://localhost/common/foxisapi.dll/tmsmail.x2.isapi?<PROCESS%20sync=''%20schema=''%20class='replicateApplication.getChanges'%20/>

Note the entire URL.

So I am trying httplib I have encoded the GET request with urllib.quote

urllib would be much easier if you don't need low level control -- it will
automatically call httplib for you.

For one, x does not contain the entire request.
"/common/foxisapi.dll/tmsmail.x2.isapi?" Should also be part of the
request; otherwise, the server doesn't know which script to call. Your
script is requesting the QUERY_STRING instead of requesting the proper
script and handing the QUERY_STRING to it. The report you are getting back
is likely your default top level script minus any rewrites or redirection.

If you just need the content of the request, then I suggest using urllib:

import urllib
url = "http://localhost/common/foxisapi.dll/tmsmail.x2.isapi?<PROCESS%20sync=''%20schema=''%20class='replicateApplication.getChanges'%20/"
content = urllib.urlopen(url).read()

Tim Harig · May 13, 2009

import urllib
url = "http://localhost/common/foxisapi.dll/tmsmail.x2.isapi?<PROCESS%20sync=''%20schema=''%20class='replicateApplication.getChanges'%20/"
content = urllib.urlopen(url).read()

forgot to urlencode:

host = "http://localhost"
request = r"""/common/foxisapi.dll/tmsmail.x2.isapi?<PROCESS sync='' schema='' class='replicateApplication.getChanges' /"""
url = host + urllib.quote(request)
content = urllib.urlopen(url).read()

Tim Harig · May 13, 2009

host = "http://localhost"
request = r"""/common/foxisapi.dll/tmsmail.x2.isapi?<PROCESS sync='' schema='' class='replicateApplication.getChanges' /"""
url = host + urllib.quote(request)
content = urllib.urlopen(url).read()

Which accidentally encodes the '?' separator. Third times a charm:
host = "http://localhost"
script = "/common/foxisapi.dll/tmsmail.x2.isapi"
getData = r"""<PROCESS sync='' schema='' class='replicateApplication.getChanges' /"""
url = host + script + '?' + urllib.quote(getData)
content = urllib.urlopen(url).read()

Carbon-based · May 13, 2009

Great, thank you very much.

Which accidentally encodes the '?' separator. Third times a charm:
host = "http://localhost"
script = "/common/foxisapi.dll/tmsmail.x2.isapi"
getData = r"""<PROCESS sync='' schema='' class='replicateApplication.getChanges' /"""
url = host + script + '?' + urllib.quote(getData)
content = urllib.urlopen(url).read()

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Help with a HTTP GET request

Paul Hemans

Chris Rebert

Tim Harig

Tim Harig

Tim Harig

Carbon-based

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