hex oct int string coversions?

[Ron Adam]

How do I covert a string hex or oct value to the correct int value?

'0764'
500
764
'0x1f4'
500

Traceback (most recent call last):
File "<pyshell#65>", line 1, in ?
int(t)
ValueError: invalid literal for int(): 0x1f4

 

[=?ISO-8859-1?Q?=22Martin_v=2E_L=F6wis=22?=]

How do I covert a string hex or oct value to the correct int value?

http://www.python.org/doc/current/lib/built-in-funcs.html#l2h-41

Martin

 

[Ron Adam]

http://www.python.org/doc/current/lib/built-in-funcs.html#l2h-41

Martin

That tells me how to convert an int to a hex or oct string using the
hex() and oct() functions, which I already know.

The int() function will convert a string to an integer. But it
doesn't understand hex or oct from a string., You can type the hex,
or oct value as an argument for the int() function on the command line
and that works correctly.

So there must be a way to do it? Am I missing a step?

_Ron

 

[Ron Adam]

That tells me how to convert an int to a hex or oct string using the
hex() and oct() functions, which I already know.

The int() function will convert a string to an integer. But it
doesn't understand hex or oct from a string., You can type the hex,
or oct value as an argument for the int() function on the command line
and that works correctly.

So there must be a way to do it? Am I missing a step?

_Ron

It was there, I wasn't looking at it correctly. int(s,0) or
int(s,8) works great. Thanks Martin. And also to Mike who pointed
it out to me in email.

I really need to get more sleep.

_Ron