How to convert '1' into '-1' and vice versa?

[-]

Is there a function to convert '1' into '-1' and vice versa?

 

[Knute Johnson]

Is there a function to convert '1' into '-1' and vice versa?

public int negate(int n) {
return -n;
}

or just;

n = -n;

 

[JScoobyCed]

Is there a function to convert '1' into '-1' and vice versa?

public class Negate {

private Object lock = new Object();

public static int negate(int n) {
int tmp = 0;
synchronized(lock) {
tmp = n - (2 * n);
int loop = 0;
if(n > 0) {
loop = (new Random()).nextInt(n*1000);
for(int i=0; i<loop; i++) {
int j = i * (-1);
if((0 - j) == n) {
tmp = j;
break;
}
}
}
else {
loop = (new Random()).nextInt((-n)*1000);
for(int i=0; i<loop; i++) {
int j = i;
if((0 - j) == n) {
tmp = j;
break;
}
}
}
}
return tmp;
}

We can still find more complexe :-D

 

[.]

Is there a function to convert '1' into '-1' and vice versa?

What datatype is '1' and '-1'? This is not proper notation for Java. The
use of single quotes denotes a char but the '-1' would be an invalid char.

So are you asking to convert "1" to "-1"? Or maybe '1' to "-1"? Or more
likely 1 to -1? The last option is very easy. i.e.

int n = 1;
n = -n;

 

[Knute Johnson]

What datatype is '1' and '-1'? This is not proper notation for Java. The
use of single quotes denotes a char but the '-1' would be an invalid char.

So are you asking to convert "1" to "-1"? Or maybe '1' to "-1"? Or more
likely 1 to -1? The last option is very easy. i.e.

int n = 1;
n = -n;

..

What is it you are really trying to do?

 

[Roland]

.

What is it you are really trying to do?

I don't think that OP ("-") is the same person you are replying to (".").
--
Regards,

Roland de Ruiter
` ___ ___
`/__/ w_/ /__/
/ \ /_/ / \

 

[-]

What datatype is '1' and '-1'? This is not proper notation for Java. The
use of single quotes denotes a char but the '-1' would be an invalid char.

So are you asking to convert "1" to "-1"? Or maybe '1' to "-1"? Or more
likely 1 to -1? The last option is very easy. i.e.

int n = 1;
n = -n;

Indeed, the last option was what I wanted to do.

I was thinking along the line that since there is a Math.abs(double)
function, I thought there was a method to do what I wanted.

Didn't realise it was that easy. No wonder it doesn't warrant a method
of its own.

 

[Wibble]

public class Negate {

private Object lock = new Object();

public static int negate(int n) {
int tmp = 0;
synchronized(lock) {
tmp = n - (2 * n);
int loop = 0;
if(n > 0) {
loop = (new Random()).nextInt(n*1000);
for(int i=0; i<loop; i++) {
int j = i * (-1);
if((0 - j) == n) {
tmp = j;
break;
}
}
}
else {
loop = (new Random()).nextInt((-n)*1000);
for(int i=0; i<loop; i++) {
int j = i;
if((0 - j) == n) {
tmp = j;
break;
}
}
}
}
return tmp;
}

We can still find more complexe :-D

I love that! You're my hero!

 

[Antti S. Brax]

I love that! You're my hero!

That is bullshit. If you're going to write a comedy response
for a trivial question, at least make it work properly.

Hint 1: the code will fail miserably if n is greater than
Integer.MAX_VALUE / 1000.

Hint 2: you can't access instance variables from static
context.

Also, it is trivial to make a complex example by adding
useless code (ie. the unnecessary synchronization block).
You might as well take the source code for Tomcat, embed
it inside your method and then return -n in the end.

If you need a hero in the field of comedy coding, please
read this: http://home.tiac.net/~cri/2001/badsort.html