How to delete the space characters from the string

[jayapal]

Hi all,

Is there any library function in order to delete the space characters
from the given stirng.

Thanks,
Jay

 

[Richard Heathfield]

jayapal said:

Hi all,

Is there any library function in order to delete the space characters
from the given stirng.

No, but see K&R2, page 47.

 

[santosh]

Hi all,

Is there any library function in order to delete the space characters
from the given stirng.

Not in Standard C, but it's pretty easy to roll your own. If you are
having problems doing so, then by all means post your code along with
your question.

PS. If you do "roll your own" you might want to make the function more
generic by designing it to remove all occurrences of a user specified
character, rather than creating it for the specific case of a space
character alone.

 

[Mark Bluemel]

Hi all,

Is there any library function in order to delete the space characters
from the given stirng.

How about looking in the standard?

The answer is "no", anyway. But it wouldn't be difficult to write one,
would it?

Untested code follows:-

/* "squeeze a string "in place" */
char *removeSpaces(char * string) {
char *source = string;
char *target = string;

while(*source) {
if (*source != ' ') {
*target++ = *source;
}
source++;
}
*target = '\0';
return string;
}

 

[Richard]

How about looking in the standard?

So we move from "RTFM" to "why don't you look in the standard". Despite
the standard (standard, not the draft )not being available for free
online and almost inaccessible to anyone without formal CS training.

The answer is "no", anyway. But it wouldn't be difficult to write one,
would it?

Possibly for a C noob...

Untested code follows:-

/* "squeeze a string "in place" */
char *removeSpaces(char * string) {
char *source = string;
char *target = string;

/*alternatively and as untested something like the following which uses
natural termination like strcpy.*/

char c;
while(*target = *source++)
if(*target)!=' ')
target++;

/*