how to get all repeated group with regular expression

[scsoce]

say, when I try to search and match every char from variable length
string, such as string '123456', i tried re.findall( r'(\d)*, '12346' )
, but only get '6' and Python doc indeed say: "If a group is contained
in a part of the pattern that matched multiple times, the last match is
returned."
cause the regx engine cannot remember all the past history then ? is it
nature to all regx engine or only to Python ?

 

[Hrvoje Niksic]

say, when I try to search and match every char from variable length
string, such as string '123456', i tried re.findall( r'(\d)*, '12346'
) , but only get '6' and Python doc indeed say: "If a group is
contained in a part of the pattern that matched multiple times, the
last match is returned."

Well, re.findall(r'(\d)*', '123456') returns ['6', ''] for me, but
that's because re.findall returns the entire match, regardless of
group contents. What you probably meant was something like
re.search(r'(\d)*', '123456').group(1), which indeed returns '6', the
contents of the last group matched.

What problem are you trying to solve? Depending on this, the best
tool might be either findall/finditer, or search/match.