How to get the class name inside the class's member function?

[Peng Yu]

Hi,

__FUNCTION__ can give the function name. Is there any variable for
class name?

Thanks,
Peng

 

[Jim Langston]

Hi,

__FUNCTION__ can give the function name. Is there any variable for
class name?

If you are lucky, typeid( *this ).name()
Lucky meaning it may do so on some implementations, others it may not.
..name() is not guaranteed to have any value afaik.

On my system, and compiler (VC++ Express 2008) the following program
outputs:
class Foo

Your mileage may vary.

#include <iostream>

class Foo
{
public:
Foo()
{
std::cout << typeid( *this ).name() << "\n";
}
};

int main()
{
Foo Bar;
}

 

[tony_in_da_uk]

If you are lucky, typeid( *this ).name()
Lucky meaning it may do so on some implementations, others it may not.
.name() is not guaranteed to have any value afaik.

Similarly, if you're lucky enough to get to use GCC,
__PRETTY_FUNCTION__ should contain the scoping namespaces/classnames
(and return and argument types). So, some parsing required....

Tony