File.dirname(__FILE__) will give you the current file's path.
The current file may be accessed with a relative path. If you need the
absolute path,
make sure you expand it: File.expand_path(File.dirname(__FILE__))
Also, if I have a module, within a function, how do I get the parent
directory (full path) of that module?
If __FILE__ is used in that module, it will refer to the file containing
that module.
If the module is under your control, you can add a method that provides
this:
module MyModule
def this_file
__FILE__
end
end
Otherwise, as has been noted, since a module name does not have to have
any
relation to the filename it is in, there is no way (AFAIK) to find the
file containing a
particular module unless you open the current file and parse for any
require
or load calls (recursively using the current environment for searching
for files)
and look for the module declaration line. (Note that a file may have
been required
using a path, so you must parse the current script to find where files
have been
located.)
Of course, a module could have content added in multiple files...
