How to make a method into a property without using the @property decorator

[Phlip]

Pythonistas:

Here's the property decorator:

@property
def foo(self): return 'bar'

If I generate foo dynamically, how to I make it a property?

setattr(self, 'foo', property(lambda: 'bar'))

Variations of that are apparently not working.

(I'm heading for a proxy pattern, where if you never call the
generated prop, you never hit the database to load it into memory.)

 

[Peter Otten]

Pythonistas:

Here's the property decorator:

@property
def foo(self): return 'bar'

If I generate foo dynamically, how to I make it a property?

setattr(self, 'foo', property(lambda: 'bar'))

Variations of that are apparently not working.

You have to put the property descriptor into the class, not an instance:
.... pass
....

'FOO'

(I'm heading for a proxy pattern, where if you never call the
generated prop, you never hit the database to load it into memory.)

You may be better off with __getattr__().

Peter

 

[Phlip]

You may be better off with __getattr__().

Ayup, thanks. (Maybe I should have googled for "python equivalent of
ruby method_missing", hmm?