If number is 0 return zero else return one

[Lakshmi Sreekanth]

Hi,

My problem: I need to return 0 if number = 0 other wise return value
should be 1.

Condition: Only by using below operators, We should not use any loops
or if or switch or any thing

Legal ops: ! ~ & ^ | + << >>

Waiting for clue.

Regards,
Laks ..... Sree.....

 

[Noob]

My problem: I need to return 0 if number = 0 other wise return value
should be 1.

Condition: Only by using below operators, We should not use any loops
or if or switch or any thing

Legal ops: ! ~ & ^ | + << >>

Hint: the "!" operator maps 0 to 1 and everything else to 0.

 

[Rich Webb]

Hi,

My problem: I need to return 0 if number = 0 other wise return value
should be 1.

Condition: Only by using below operators, We should not use any loops
or if or switch or any thing

Legal ops: ! ~ & ^ | + << >>

Waiting for clue.

Can do. However, please provide your teacher's email address so that we
can send him/her the answer directly. Much more efficient ...

 

[Nick Keighley]

Lakshmi Sreekanth wrote:



Hint: the "!" operator maps 0 to 1 and everything else to 0.

run this

#include <stdio.h>

int main (void)
{
printf ("%d %d\n", 1 == 0, 0 == 0);
return 0;
}

does that give a hint?

 

[Ben Bacarisse]

My problem: I need to return 0 if number = 0 other wise return value
should be 1.

Condition: Only by using below operators, We should not use any loops
or if or switch or any thing

Legal ops: ! ~ & ^ | + << >>

Waiting for clue.

You have only one object to consider (number) and 9 operators (+ is
two, yes?) so you can get the answer by listing all the possibilities
in some logical order. I suggest some sort of "increasing
complexity":

No operators:
number

1 operator:
!number
~number
+number
number & number
number ^ number
number | number
number + number
number << number
number >> number

2 operators:
!!number
!~number
!+number
~!number
~~number
~+number
+!number
+~number
++number
!number & number
!number ^ number
!number | number
!number + number
!number << number
!number >> number
number & !number
number ^ !number
number | !number
number + !number
number << !number
number >> !number
...
number >> +number

3 operators:
!!!number
... [very long list]
+number >> +number

and so on. This list never ends, but you can presume that if there is
an answer it will crop up reasonably soon (hint: give up once you've
got to +number >> +number using the ordering above).

You don't say what type "number" has. If it has to work for a lot of
different types, you can cut this list down a lot. Working this way
may look tedious by you will learn a lot about how C's operators are
defined to work. Once you've done a few you'll be able to check them
very quickly.

Get extra credit by saying how many expressions there are in the list
for "n operators".

 

[Noob]

run this

#include <stdio.h>

int main (void)
{
printf ("%d %d\n", 1 == 0, 0 == 0);
return 0;
}

does that give a hint?

Nick,

Why are you replying to me?

NB: the "==" operator is not accepted in the OP's pointless game.

 

[Chris M. Thomasson]

Hi,

My problem: I need to return 0 if number = 0 other wise return value
should be 1.

Condition: Only by using below operators, We should not use any loops
or if or switch or any thing

Legal ops: ! ~ & ^ | + << >>

Waiting for clue.

logical negation

 

[Mug]

Hint: the "!" operator maps 0 to 1 and everything else to 0.

my friend found this in 5 minutes in our xml course

#include <stdio.h>
int main(int argc, const char *argv[])
{
int n=0;
printf("answer %d\n",!(!n));
return 0;
}

not need the explication i think

 

[Keith Thompson]

Hint: the "!" operator maps 0 to 1 and everything else to 0.

my friend found this in 5 minutes in our xml course

#include <stdio.h>
int main(int argc, const char *argv[])
{
int n=0;
printf("answer %d\n",!(!n));
return 0;
}

not need the explication i think

Great. Now Lakshmi Sreekanth has the solution she(?) was looking
for, and is relieved of the terrible burden of either thinking
or learning.

I've got this project at work. Can you do that for me too?
Don't worry, I'll take all the credit.

 

[Kenny McCormack]

Great. Now Lakshmi Sreekanth has the solution she(?) was looking
for, and is relieved of the terrible burden of either thinking
or learning.

I've got this project at work. Can you do that for me too?
Don't worry, I'll take all the credit.

Actually, if you posted all the particulars here (or, if it is large,
which I doubt, given your general displayed skill level, post it on a
website for us all), somebody probably will do it all for you. Of
course, you will have to live with their solution, which may not be to
your liking. That's the price of getting things for free.

Just consider Linux...

 

[Nick Keighley]

Nick,

Why are you replying to me?

because the original post does not appear on my news reader.

NB: the "==" operator is not accepted in the OP's pointless game.

missed that. Yes it is a stupid game

 

[Phil Carmody]

logical negation

You'll have to tell him twice if he's to believe you!

Then again, I prefer toggling with a ^1.

Phil