initializing cooperative method

[jelle]

Hi,

I'm writing a bunch of abstract classes and I'd like to delegate the
arguments of the concrete class the to abstract one. I was surprised
to see that the print statement in the abstract class isn't executed.
But moreover, I'd like to find out an idiom that allows one to
delegate arguments in the inherited class. Any ideas?

Thanks,

-jelle



class Abstract(object):
def __init__(self, a='a', b='b'):
self.a, self.b = a, b
print a, b

class Concrete(Abstract):
def __init__(self, a='AAA', b='BBB'):
super(Abstract, self).__init__( a=a, b=b )
print a, b

c = Concrete(a=1) 1 BBB

 

[Steven D'Aprano]

Hi,

I'm writing a bunch of abstract classes and I'd like to delegate the
arguments of the concrete class the to abstract one. I was surprised to
see that the print statement in the abstract class isn't executed. But
moreover, I'd like to find out an idiom that allows one to delegate
arguments in the inherited class. Any ideas?

Change the call to super() in Concrete from:

super(Abstract, self).__init__(a, b)

to

super(Concrete, self).__init__(a, b)

 

[jelle]

Ai, calling super(Abstract) is just getting object, sure...

However, I'm still curious to know if there's a good idiom for
repeating the argument in __init__ for the super(Concrete,
self).__init__ ?

Thanks,

-jelle

 

[jelle]

Ai, calling super(Abstract) is just getting object, sure...

However, I'm still curious to know if there's a good idiom for
repeating the argument in __init__ for the super(Concrete,
self).__init__ ?

Thanks,

-jelle

 

[Jonathan Gardner]

Ai, calling super(Abstract) is just getting object, sure...

However, I'm still curious to know if there's a good idiom for
repeating the argument in __init__ for the super(Concrete,
self).__init__ ?

If you don't know what the arguments are, you can use *args and
**kwargs.

class Concrete(Abstract):
def __init__(self, *args, **kwargs):
super(Concrete, self).__init__(*args, **kwargs)